`lim_(n->oo)pi/(6n)[sec^2(pi/(6n))+sec^2(2.pi/(6n))+...........+sec^2((n-1)pi/(6n))+4/3]=`

Lt_(ntooo)(1)/(n)[sec^(2)""(pi)/(4n)+sec^(2)""(2pi)/(4n)+......+sec^(2)""(npi)/(4n)]=

The value of lim_(ntooo)(1)/(n)[sec^2""(pi)/(4n)+sec^2""(2pi)/(4n)+....+sec^2""(npi)/(4n)] is

lim_ (n rarr oo) (pi) / (6n) [sec ^ (2) ((pi) / (6n)) + sec ^ (2) (2 * (pi) / (6n)) + .... ..... + sec ^ (2) ((n-1) (pi) / (6n)) + (4) / (3)]

The value of lim_(nrarroo)(1)/(n)[sec^(2)""(pi)/(4n)+sec^(2)""(2pi)/(4n)+….+sec^(2)""(npi)/(4n)] is

Lim_(n->oo)[1/n^2 * sec^2 (1/n^2)+2/n^2 * sec^2 (4/n^2)+..............+1/n * sec^2 1]

The value of lim_(n->oo) [tan(pi/(2n)) tan((2pi)/(2n))........tan((npi)/(2n))]^(1/n) is

The value of lim_(n->oo) [tan(pi/(2n)) tan((2pi)/(2n))........tan((npi)/(2n))]^(1/n) is

The value of lim_(n->oo) [tan(pi/(2n)) tan((2pi)/(2n))........tan((npi)/(2n))]^(1/n) is

f(n) = cot^2 (pi/n) + cot^2\ (2 pi)/n +...............+ cot^2\ ((n-1) pi)/n, ( n>1, n in N) then lim_(n rarr oo) f(n)/n^2 is equal to (A) 1/2 (B) 1/3 (C) 2/3 (D) 1