7c(log x)^(x)+x^(log x)

Solve 7^(log x) + x^(log 7)=98

Solve : 7^(log x)=98-x^(log 7)

Solve : 7^(log x)=98-x^(log 7)

int_(1)^(e )(1)/(6x(log x)^(2)+7x log x + 2x)dx=

If x^(y)=e^(x-y), then (dy)/(dx) is (1+x)/(1+log x)(b)(1-log x)/(1+log x)(c) not defined (d) (log x)/((1+log x)^(2))

Ify=2^(log x),then(dy)/(dx)is(a)(2^(log x))/(log2)c)(2^(log x))/(x)(d)(2^(log x)xx log2)/(x)

int (1)/( x (log x) log (log x) ) dx is equal to a) log (log x) + C b) log | log (x log x) + C c) log | log | log (log x) || + C d) log | log (log x) | + C

The value of int(1)/(x+x log x)dx is 1+log x(b)x+log x(c)x log(1+log x)(d)log(1+log x)

int(log(x+1)-log x)/(x(x+1))dx= (A) log(x-1)log x+(1)/(2)(log x-1)^(2)-(1)/(2)(log x)^(2)+c (B) (1)/(2)(log(x+1))^(2)+(1)/(2)(log x)^(2)-log(x+1)log x+c (C) -(1)/(2)(log(x+1)^(2))-(1)/(2)(log x)^(2)+log x*log(x+1)+c (D) [log(1+(1)/(x))]^(2)+c