(cosec A-sin A)(sec A-cos A)=1

Prove the following identity,where the angles involved are acute angles for which the expressions are defined.( ix) (csc A-sin A)(sec A-cos A)=(1)/(tan A+cot A)[ Hint : Simplify L.HS and RHS separately]

Prove that : (cosec A-sin A ) (sec A-cos A)=sinA cosA

Prove the following identities : (cosec A - sin A) (sec A - cos A) (tan A + cot A) = 1

Prove that : (cosec A - sin A) (sec A - cos A) sec^(2) A = tan A

What is the value of (cosec A - sin A) (sec A - cos A) (tan A + cot A) ?

Prove that ("cosec"A-"sin"A)("sec"A-"cos"A)"sec"^(2)A="tan"A .

(cosec A - sin A)^2 + (sec A - cos A)^2 - (cot A - tan A)^2 is equal to

Prove that (cos7A)/(sec A)-(sin7A)/(cosec A)=cos8A

Prove that (i) (tan A+ sin A)/(tan A- sin A)= (sec A+1)/(sec A-1) (ii) (cot A- cos A)/(cot A+ cos A)= ("cosec" A-1)/("cosec" A+1)

Prove that (sin A)/(sec A + tan A -1)+ (cos A)/("cosec "A +cot A-1)=1