अवकल समीकरण `(dy)/(dx)+(1+y^2)/y=0` को हल कीजिए|

solve: dy/dx+(1+y^2)/y=0

(dy)/(dx)=2y,(y>0)

Solve : dy/dx+(1+y^2)/y=0 .

dy/dx = 2xy , y(0) = 1

Solve the differential equation : (dy/dx) - (1 + y^2)/y = 0

If x=logp and y=1/p ,then (a) (d^2y)/(dx^2)-2p=0 (b) (d^2y)/(dx^2)+y=0 (c) (d^2y)/(dx^2)+(dy)/(dx)=0 (d) (d^2y)/(dx^2)-(dy)/(dx)=0

If x=logp and y=1/p ,then (a) (d^2y)/(dx^2)-2p=0 (b) (d^2y)/(dx^2)+y=0 (c) (d^2y)/(dx^2)+(dy)/(dx)=0 (d) (d^2y)/(dx^2)-(dy)/(dx)=0