` 3-8(2x-y)+4(2x-y)^2`

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))

Write the given statement as an algebraic statement and then simplify Five times the sum of 8y-[3x-4(2-3y)] and 2x-2(5+2y) is added to 2x-(8-y)''

If x:y=4:5 , then (2x+3y): (8x-5y) is equal to :

For hyperbola whose center is at (1,2) and the asymptotes are parallel to lines 2x+3y=0 and x+2y=1, the equation of the hyperbola passing through (2,4) is (2x+3y-5)(x+2y-8)=40(2x+3y-8)(x+2y-8)=40(2x+3y-8)(x+2y-5)=30 these

Factorize each of the following algebraic expressions: (1) (x-y)^2+(x-y) (2) 6(a+2b)-4(a+2b)^2 (3) a(x-y)+2b(y-x)+c(x-y)^2 (4) -4\ (x-2y)^2+8(x-2y)

From the sum of x^2+3y^2-6x y ,2x^2-y^2+8x y , y^2+8 and x^2-3x y\ subtract -3x^2+4y^2-x y+x-y+3.

From the sum of x^2+3y^2-6x y ,2x^2-y^2+8x y , y^2+8 and x^2-3x y\ subtract -3x^2+4y^2-x y+x-y+3.

2x+3y=8 4x-5y=-6

The factors of x^(2)+4y^(2)+4y-4xy-2x-8 are (a)(x-2y-4)(x-2y+2)(b)(x-y+2)(x-4y-4)(c)(x+2y-4)(x+2y+2) (d) none of these