NO_(2)longrightarrow(:hat N=C-=C longrightarrow(I)-OCH_(3)(HgSO_(4)/H_(2)SO_(4))/(longrightarrow)A(" major product ")

CH-=C-COOHoverset(HgSO_(4) // H_(2)SOH_(4))rarr product (A) is

Ph-C-=C-CH_(3)underset(HgSO_(4))overset(H_(2)O, H_(2)SO_(4))rarrP Major product 'P' will be:

CH_3-C-=CH overset(HgSO_4, H_2SO_4)to Major product is :

In a radioactive decay sequence A (lambda_(1))/(longrightarrow) B (lambda_(2))/(longrightarrow) C (lambda_(3))/ (longrightarrow) D What is the ratio of numbers of atoms of A to the number of atoms of B after long time interval starting with pure A .The mean lives of A and B are 20 hours and "30" minutes respectively

Ph - C -= C-CH_(3) overset(Hg^(2+)//H_(2)SO_(4)(aq)) to A The major product (A) formed is -

Ph - C -= C-CH_(3) overset(Hg^(2+)//H_(2)SO_(4)(aq)) to A The major product (A) formed is -

Hydration of in presence of H_(2)SO_(4) // HgSO_(4) gives ( as a major product )

Predict the correct intermediate and product in the following reaction H_(3)C-C-=H underset(HgSO_(4))overset(H_(2)O, H_(2)SO_(4))rarr "Intermediate (A)" rarr "Product (B)"

In the following reaction C_(3)H_(2)underset(HgSO_(4)//H_(2)SO_(4))overset(H_(2)O)rarrXhArrCH_(3)CHO What is X