[" A body of mass "1.0kg" is falling with an acceleration of "],[10m/sec^(2)" .Its apparent weight will be "(g=10m/sec^(2))]

A body of mass 1.0 kg is falling with an acceleration of 10 m//s^(2) . Its apparent weight will be (g=10m//sec^(2))

A man of weight 80 kg is standing in an elevator which is moving with an acceleration of 6m//s^(2) in upward direction. The apparent weight of the man will be (g=10m//s^(2))

A man of weight 80 kg is standing in an elevator which is moving with an acceleration of 6m//s^(2) in upward direction. The apparent weight of the man will be (g=10m//s^(2))

The mass of lift is 500 kg. When it ascends with an acceleration of 2m//s^(2) ,the tension in the cable will be [g=10m//s^(2)]

Mass of a person sitting in a lift is 50 kg . If lift is coming down with a constant acceleration of 10 m//sec^(2) . Then the reading of spring balance will be (g=10m//sec^(2))

A man of mass 75 kg is standing in an elevator which is moving with an acceleration of 5 m//s^2 in upward direction.The apparent weight of the man will be (g=10 m//s^2)

The apparent weight of the body, when it is travelling upwards with an acceleration of 2m//s^(2) and mass is 10 kg , will be

A block of mass 2 kg rests on the floor of an elevator , which is moving down with an acceleration 'g' , then the apparent weight of the block is [ take g = 10 m//s^(2) ]

A block of mass 2 kg rests on the floor of an elevator , which is moving down with an acceleration 'g' , then the apparent weight of the block is [ take g = 10 m//s^(2) ]