" (2) "[" ซो "2cos theta+sin theta=1" slu "d" ) "],[4cos theta+3sin theta=]

If 2cos theta+sin theta=1 then the value of 4cos theta+3sin theta is

2 cos (theta - pi //2) + 3 sin (theta + pi//2) - (3sin theta + 2 cos theta ) = ? A. cos theta - sin theta B. sin theta - cos theta C. sin theta + cos theta D. cot theta - tan theta .

4 sin theta * cos^(3) theta-4 cos theta * sin ^(3)theta= A) 4 cos theta B) cos 4 theta C) 4 sin theta D) sin 4 theta

Prove that : (1-sin theta cos theta)/ (cos theta (sec theta - cosec theta)) times (sin^2 theta - cos^2 theta)/(sin^3 theta + cos^3 theta) = sin theta

sin theta+sin2 theta+sin3 theta=1+cos theta+cos2 theta

If 3sin theta =2 cos theta , then (4sin theta - cos theta)/(4cos theta+sin theta) is equal to :

Prove that (cos^3 theta-sin^3 theta)/(cos theta-sin theta) = 1+cos theta sin theta

Prove that: (sin^(3) theta + cos^(3) theta)/(sin theta + cos theta) = 1-sin theta cos theta

Evaluate the following determinants: (b) |(cos theta, -sin theta),(sin theta, cos theta)| = cos theta (cos theta) - sin theta(-sin theta) = cos^(2) theta + sin^(2) theta = 1

If A= [[cos theta,-sin theta],[sin theta,cos theta]] ,then Adj A is (a) [[cos theta,-sin theta],[cos theta,sin theta]] (b) [[1,0],[0,1]] (c) [[cos theta,sin theta],[-sin theta,cos theta]] (d) [[-1,0],[0,-1]]