[" If "S_(1)" is the sum of an A.P.of 'n' odd number of terms and "S_(2)" is the sum of terms of the series in odd "],[" places,then "(S_(1))/(S_(2))=]

If S_1 is the sum of an AP of 'n' odd number of terms and S_2 be the sum of the terms of series in odd places of the same AP then S_1/S_2 =

If S_1 is the sum of an AP of 'n' odd number of terms and S_2 be the sum of the terms of series in odd places of the same AP then S_1/S_2 =

If S_1 is the sum of an AP of 'n' odd number of terms and S_2 be the sum of the terms of series in odd places of the same AP then S_1/S_2 =

If S_1 is the sum of an AP of 'n' odd number of terms and S_2 be the sum of the terms of series in odd places of the same AP then S_1/S_2 =

If S_1 is the sum of an AP of n odd number of terms and S_2 be the sum of terms of series in odd places of the same AP, then (S_1)/(S_2)= a.     (2n)/(n+1) b.     n/(n+1) c.     (n+1)/(2n) d.     (n+1)/n

In a sequence, if S_n is the sum of n terms and S_(n-1) is the sum of (n-1) terms, then the nth term is _________.

The first term of an AP.of consecutive integer is p^(2)+1. The sum of (2p+1) terms of this series can be expressed as

S_(n) is the sum of n terms of an A.P. If S_(2n)= 3S_(n) then prove that (S_(3n))/(S_(n))= 6

If S_(n) denotes the sum of first n terms of an A.P. and S_(2n)= 3S_(n) , then (S_(3n))/(S_(n))=

Let S_1 be the sum of first 2n terms of an arithmetic progression. Let S_2 be the sum first 4n terms of the same arithmeti progression. If (S_(2)-S_(1)) is 1000, then the sum of the first 6n term of the arithmetic progression is equal to :