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If ax^2 + bx + c = 0 and bx^2 + cx+a= 0 ...

If `ax^2 + bx + c = 0 and bx^2 + cx+a= 0` have a common root and `a!=0` then `(a^3+b^3+c^3)/(abc)` is A. `1` B. `2` C. `3` D. `9`

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