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[" Conductivity of "2.5times10-4M" ,points "],[" methanoic acid is "5.25times10-5],[" S "cm-1" .Calculate its molar "],[" conductivity and degree of "],[" dissociation.Given: "lambda O(H+)=],[349.5Scm2mol-1" and "],[lambda O(HCOO-)=50.5Scm2],[" mol-1."]

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Conductivity of 2.5xx10^(-4)M methanoic acid is 5.25xx10^(-5)Scm^(-1) . Calculate its molar conductivity and degree of dissociation (Given lambda^@(H^+)=349.5Scm^2mol^(-1) and lambda^@(HCOO)=50.5 Scm^2mol^(-1) )

Conductivity of 2.5 xx 10^(-4) M methonoic acid is 5.25 xx 10^(-5) S cm^(-1) . Calculate its molar Condcutivity and degree of dissociation. Given : lambda^(@) ( H^(+) = 349.5 S cm^(2) "mol"^(-1) and lambda^(@) ( HCOO^(-)) = 50.5 S cm^(2) "mol"^(-1) .

Conductivity of 2.5xx10^(-4) M methanoic acid is 5.25xx10^(-5)S com^(-1) . Calculate its molar conductivity and degree of dissociation. "Given ":lamda^(0)(H^(+))=349.5 S cm^(2) mol^(-1) and lamda^(0)(HCOO^(-))=50.5 S cm^(2) mol^(-1).

(b) Conductivity of \(2\times10^{-3}\) M methanoic acid is \(8\times10^{-5}Scm^{-1}\) Calculate its molar conductivity.

The conductivity of 0.001 mol L^-1 solution of CH_3COOH is 3.905xx10^-5 S cm^-1 . Calculate the molar conductivity and degree of dissociation Give that lambda^@(H^+)=349.65 S cm^2 mol^-1 and lambda^@(CH_2COO^-40.9 S cm^2 mol^-1 .