" 11.) Check whether "T=2 pi sqrt((l)/(g))" is dimensionally correct or not "

Check whether the equation mv^2=mgh is dimensionally correct or not.

Show that the expression of the time period T of a simple pendulum of length l given by T = 2pi sqrt((l)/(g)) is dimensionally correct

Show that the expression of the time period T of a simple pendulum of length l given by T = 2pi sqrt((l)/(g)) is dimensionally correct

The correctness of an equation can be checked using the principle of homogenity in dimensions. Using this principle check whether the equation, f=2πsqrt(l/g) is dimensionally correct,where f -frequency, l -length, g acceleration due to gravity.

Show that the expression of the time period T of a simple pendulum of length l given by T = 2pi sqrt((l)/(g)) is dimensionally currect

Show that the expression of the time period T of a simple pendulum of length l given by T = 2pi sqrt((l)/(g)) is dimensionally currect

Check whether the equation T=2πsqrt ( m/g) is dimensionally correct.Where T is the Time period of a simple pendulum , m is the mass of the bob and g is the acceleration due to gravity

Check whether 1/2 mv^2 = mgh equation is dimensionally correct or not.Here m = mass of material,v = velocity,g = gravitational acceleration,h= height.

Check whether the relation S = ut + (1)/(2) at^(2) is dimensionally correct or not , where symbols have their usual meaning .