y=4x-x^(2)" and "y=5-2x

Find the area enclosed with in the curve y=4x-x^(2), y=5-2x

Find the area enclosed with in the curve y=4x-x^(2), y=5-2x

x"@"y=(x+y)^(2) x#y=(x-y)^(2) (2" @ "2)+(3#3)-(4"@"4)+(5#5) is equal to :

From the sum of 3x+2x^2-y^2 and 6y-5y^2+3x^2+4x , subtract the sum of x^2-2y^2+3x-5y and 3x^2+2y^2-4x-y

Solve for (x - 1)^(2) and (y + 3)^(2) , 2x^(2) - 5y^(2) - x - 27y - 26 = 3(x + y + 5) and 4x^(2) - 3y^(2) - 2xy + 2x - 32y - 16 = (x - y + 4)^(2) .

From the sum of 5x-3x^2+y^2 and 8x-3y^2-x^2+x subtract the sum of 2x^2+y^2+4x-2y and x^2+y^2-3x-2y

The general solution of differential equation (x^6y^4+x^2)dy=(1-x^5y^5-x y)dx is (a)In |x|=x y+(x^4y^4)/4+C (b)In |y|=x y+(x^5y^5)/4+C (c)In |y|=x y+(x^5y^5)/2+C (d)In |x|=x y+(x^4y^4)/5+C

Find the products: (2x+y)(2x-y)(4x^(2)+y^(2)(x-(y)/(5)-1)(x+(y)/(5)+1)

If 2x + y = 23 and 4x - y = 19 , then find the values of 5y - 2x and (y)/(x) - 2 .