[" Show that the area of the triangle formed by the lines "],[ax^(2)+2hxy+by^(2)=0" and "lx+my+n=0" is "|(n^(2)sqrt(h^(2)-ab))/(am^(2)-2hlm+bl^(2))|]

Show that the area of the triangle formed by the lines ax^2 + 2hxy + by^2 = 0 and lm + my + n =0 is (n^2 sqrt(h^2 - ab))/(|am^2 - 2hlm + bl^2|)

Show that the area of the triangle formed by the lines ax^2+2hxy+by^2=0 and lx+my+n=0 is (n^2sqrt((h^2-ab)))/(|(am^2-2hlm+bl^2)|)

Show that the area of the triangle formed by the lines ax^2+2hxy+by^2=0 and lx+my+n=0 is (n^2sqrt((h^2-ab)))/(|(am^2-2hlm+bl^2)|)

Show that the area of the triangle formed by the lines ax^2+2hxy+by^2=0 and lx+my+n=0 is (n^2sqrt((h^2-ab)))/(|(am^2-2hlm+bl^2)|)

Show that the area of the triangle formed by the lines ax^2+2hxy+by^2=0 and lx+my+n=0 is (n^2sqrt((h^2-ab)))/(|(am^2-2hlm+bl^2)|)

If a+b=2h, then the area of the triangle formed by the lines ax^(2)+2hxy+by^(2)=0 and the line x-y+2=0, in sq.units is

Prove that the aea of the triangle formed by y=x+c and the pair of lines ax^(2)+2hxy=by^(2)=0 is (e^(2)sqrt(h^(2)-ab))/(|a+b+2h|) sq. units.

Prove that orthocentre of triangle formed by pair of lines ax^(2)+2hxy+by^(2)=0 an the line lx+my+n=0 is (kl, km) where k=(-n(a+b))/(am^(2)-2hlm+bl^(2))