Two bodies are projected simultaneously with the same velocity of `19.6 m//s` from the top of a tower one vertically upwards and the other vertically downwards. As they reach the ground, the time gap is

Two balls are projected simultaneously with the same speed from the top of a tower, one vertically upwards and the other vertically downwards. They reach the ground in 9 s and 4 s, respectively. The height of the tower is (g=10 m//s^(2))

Two balls are projected simultaneously with the same velocity u from the top of a tower, one vertically upwards and the other vertically downwards. Their respective times of the journeys are t_(1) and t_(2) At the time of reaching the ground, the ratio of their final velocities is

Two balls are projected simultaneously with the same speed from the top of a tower, one vertically upwards and the other vertically downwards. They reach the ground in 9 second and 4 second respectively. The height of the tower is:

Two balls are projected simultaneously with the same speed from the top of a tower, one vertically up wards and the other vertically downwards. If the first bll strikes the ground with speed 20 m//s then speed of second ball when it strikes the ground is.

Two balls are projected simultaneously with the same speed from the top of a tower-one upwards and the other downwards.If they reach the ground in 6s and 2s ,the height of the tower is

Two balls are projected simultaneously with the same speed from the top of a tower-one upwards and the other downwards.If they reach the ground in 6s and 2s ,the height of the tower is