if `ax^2-(2a+3)x + (3+5a) =0` has no real roots then ` a` lies in the interval ?

If the equation has no real root, then lamda lies in the interval

If the equation has no real root, then lamda lies in the interval

If z^3+(3+2i)z+(-1+i a)=0 has one real roots, then the value of a lies in the interval (a in R)

If z^3+(3+2i)z+(-1+i a)=0 has one real root, then the value of a lies in the interval (a in R) a.(-2,1) b. (-1,0) c. (0,1) d. (-2,3)

If z^3+(3+2i)z+(-1+i a)=0 has one real roots, then the value of a lies in the interval (a in R) (-2,1) b. (-1,0) c. (0,1) d. (-2,3)

If z^3+(3+2i)z+(-1+i a)=0 has one real root, then the value of a lies in the interval (a in R) a. (-2,1) b. (-1,0) c. (0,1) d. (-2,3)

If the equation x^4- λx^2+9=0 has four real and distinct roots, then lamda lies in the interval

If the equation x^4- λx^2+9=0 has four real and distinct roots, then lamda lies in the interval

If the equation x^4- λx^2+9=0 has four real and distinct roots, then lamda lies in the interval