The point `(1,4)` are inside the circle `S: x^2+y^2-6x-10y+k=0`. What are the possible values of `k` if the circle S neither touches the axes nor cut them

If the point (1, 4) lies inside the circle x^(2)+y^(2)-6x-10y+p=0 then p is:

The point (-1,0) lies on the circle x^2+y^2-4x+ 8y + k=0 . The radius of the circle is

If a point (1,4) lies inside the circle x^(2) +y^(2) - 6x -10 y +p=0 and the circle does not touch or intersect the coordinate axes , then the set of all possible values of p is the interval.

The circle x^2+y^2-2x-2y+k=0 represents a point circle when k.=

If (2,5) is an interior point of the circle x^2+y^2-8x-12y+P=0 and the circle neither cuts nor touches any one of the co-ordinate axes then :

If (2, 4) is a point interior to the circle x^(2)+y^(2)-6x-10y+lambda=0 and the circle does not cut the axes at any point, then

If (2, 4) is a point interior to the circle x^(2)+y^(2)-6x-10y+lambda=0 and the circle does not cut the axes at any point, then

If the straight line 3x + 4y = k touches the circle x^2+y^2-10x = 0, then the value of k is: