The base of a right pyramid is an equilateral triangle, each side of which is `6sqrt(3)` cm long and its height is 4 cm. Find the total surface area of the pyramid in `cm^(2)`.

The base of a right prism is an equilateral triangle of side 4 cm. Find the volume of the prism if its height is 9 cm.

Find the area of an equilateral triangle whose side is 4sqrt(3) cm.

An equilateral triangle of side 6 cm. Its area is :

The base of a right pyramid is an equilateral triangle of side 10sqrt(3) cm . If the total surface area of the pyramid is 270 sqrt(3) . Sq. cm, its height is

The base of a right pyramid is an equilateral triangle with side 8 cm, and the height of the pyramid is 24 sqrt3 cm. The volume (in cm^3 ) of the pyramid is:

The base of a right pyramid is an equilateral triangle of side 4 cm each. Each sland edge is 5 cm long. The volume of the pyramid is

The base of a right pyramid is an equilateral triangle of perimeter 8 dm and the height of the pyramid is 30sqrt(3) cm. Find the volume of the pyramid.

The base of a right pyramid is an equilateral triangle of side 4cm .The height of the pyramid is half of its slant height. The volume of the pyramid is: A) (8sqrt(3))/(9)cm^(3) B) (4sqrt(3))/(9)cm^(3) C) (16)/(3)cm^(3) D) (18)/(sqrt(3))cm^(3)

The base of a pyramid is a square whose side is 10 cm. It's slant and vertical heights are 13 and 12 . Then , find the total surface area and volume of the pyramid .