(1)/(2a+b+2x)=(1)/(2a)+(1)/(6)+(1)/(2x)

Solve for: (1)/(2a+b+2x)=(1)/(2a)+(1)/(b)+(1)/(2x)

Solve for: 1/(2a+b+2x)=1/(2a)+1/b+1/(2x)

Add :5x^(2)-(1)/(3)x+(5)/(2),-(1)/(2)x^(2)+(1)/(2)x-(1)/(3) and -2x^(2)+(1)/(5)x-(1)/(6)

The expression (1)/(1+(x)/(1-(x)/(x+2)))div ((1)/(1-x)+(1)/(1+x))/((1)/(1-x)-(1)/(1+x)) (a) (2x)/(x^(2)+2x+2) (b) (2x)/(x^(2)-1) (c) 1 (d) x^(2)-1

(2x-1)/(2x+1)+(2x+1)/(2x-1)=6

If (1)/((1+2x)(1-x^(2)))=(A)/(1+2x)+(B)/(1+x)+(C)/(1-x) then assending order of A, B, C.

If (1)/((1+2x)(1-x^(2)))=(A)/(1+2x)+(B)/(1+x)+(C)/(1-x) then assending order of A, B, C.

If A=(2x+1)/(2x-1), B=(2x-1)/(2x+1) find (1)/(A-B)-(2B)/(A^(2)-B^(2))

If tan^(-1)2x+tan^(-1)3x=(pi)/(2) , then the value of x is equal to a) (1)/(sqrt(6)) b) (1)/(6) c) (1)/(sqrt(3)) d) (1)/(sqrt(2))