Equation of the circle on the latusrectum of `y^(2)=8x` as ends of diameter is

Find the equation of the circle drawn on the line joining the centres of the circles as diameter: (i)x^(2)+y^(2)-6x+8y-20=0 and x^(2)+y^(2)+8x-6y=0

Equation of the circle concentric with x^(2)+y^(2)-8x-16y+4=0 and touches y- axis is

The equation of director circle to the circle x^(2) + y^(2) = 8 is

Find the equation of the circle the end points of whose diameters are the centres of the circles x^(2)+y^(2)+16x-14y=1 and x^(2)+y^(2)-4x+10y=2

Find the equation of the circle the end points of whose diameter are the centres of the circle : x^2 + y^2 + 6x - 14y=1 and x^2 + y^2 - 4x + 10y=2 .

Equation of the circle concentric with the circle x^(2) + y^(2) + 8x + 10 y - 7 = 0 , and passing through the centre of the circle x^(2) + y^(2) - 4x - 6y = 0 ,is

The equation of a circle C is x^(2)+y^(2)-6x-8y-11=0 . The number of real points at which the circle drawn with points (1, 8) and (0,0) as the ends of a diameter cuts the circle, C, is

Find the equation of the circle concentric with the circle x^(2)+y^(2)-8x+6y-5=0 and passing through the point (-2,-7),