`2(cos^2theta-sin^2theta)=1`

2(cos^(2)theta-sin^(2)theta)=1(theta is a positive acute angle),then cot theta is equal to

If 2(cos^(2)theta-sin^(2)theta)=1,theta is a positive acute angle , then the value of theta is

Find the general value of theta from the following equations :2(cos^(2)theta-sin^(2)theta)=1

If 2cos^(2)theta-2sin^(2)theta=1, then theta is equal to

If 2cos^(2)theta-2sin^(2)theta=1, then theta equals to

Solve for theta : cos^2 theta-sin^2 theta=1/2,0 यदि cos^2 theta-sin^2 theta=1/2,0

If theta lies in the first quadrant and cos^2 theta-sin^2 theta=1/2 , then the value of tan^2 theta+sin^2 3 theta is : यदि theta पहले चतुर्थाश में स्थित है और cos^2 theta-sin^2 theta=1/2 है, तो tan^2 theta+sin^2 3 theta का मान ज्ञात करें |

If cos^(4)theta-sin^(4)theta=(2)/(13) , find cos^(2)theta-sin^(2)theta+1 .

((1+cos theta)^2+ sin^2 theta)/ ((cosec^2 theta-1)sin^2 theta) =?

Show that (cos^(2)theta - sin^(2)theta)=(2tan theta)/((1- tan^(2)theta)) is not an identity .