Suppose a quantilty x can be dimensionally represented in terms of M,L and T, that is `[x], M^aL^bT^c`. The quantity mass

A physical quantity x can dimensionally represented in terms of M, L and T that is x=M^(a) L^(b) T^(c) . The quantity time-

A physical quantity x can dimensionally represented in terms of M, L and T that is x=M^(a) L^(b) T^(c) . The quantity time-

A physical quantity x can dimensionally represented in terms of M, L and T that is x=M^(a) L^(b) T^(c) . The quantity time-

The dimensional formula of physical quantity is [M^(a)L^(b)T^(c)] .Then that physical quantity is

The dimensional formula of physical quantity is [M^(a)L^(b)T^(c)] .Then that physical quantity is

Assertion : All physical quantities can be represented dimensionally in terms of the base quantities. Reason : A base quantity cannot be represented dimensionally in terms of remaining base quantities.

The dimensional formula of physical quantity is M^(a) L^(b) T^( c) . Then that physical quantity is

An expression of physical quantity is written as X = sqrtfrac(T)(M) , where T is the applied force and m is the mass per unit length. Find the dimensional representation of X and identify. The physical quantity. ( X = sqrtfrac(T)(m) .

An expression of physical quantity is written as (X = sqrtfrac(t)(m) where T is the applied force and m is the mass per unit length. Find the dimensional representation of X and identify the physical quantity. (X = sqrtfrac(T)(m) .