If a number of little droplets of water, each of radius `r`, coalesce to form a single drop of radius `R`, show that the rise in temperature will be given by `(3T)/J(1/r-1/R)` where `T` is the surface tension of water and `J` is the mechanical equivalent of heat.

If a number of little droplets of water each of radius r, coalesce to form a single drop of radius R, show that the rise in temperature will be given by Delta0=(3sigma)/(J)((1)/(r)-(1)/(R)) Where sigma is the surface tension of water and J is the mechanical equivalent of heat.

If a number of little droplets of water, all of the same radius r, coalesce to form a single drop of radius R, the rise in temperature will be given by (18 T)/( eta rho s) ((1)/(r ) - (1)/(R )) where T is the surface tension of water, rho is density of water and n is a dimensionless constant. Find eta .

n number of water droplets, each of radius r , coalese, to form a single drop of radius R . The rise in temperature d theta is

n number of water droplets, each of radius r , coalese, to form a single drop of radius R . The rise in temperature d theta is

If a number of small droplets off water each of radius r coalesce to form a single drop of radius R, show that the rise in temperature is given by T = ( 3 sigma )/( rho c ) [ ( 1)/( r ) - ( 1)/( R )] where sigma is the surface tension of water, rho its density and c is its specific heat capacity.

A number of water droplets each of radius r coalesce to from a drop of radius R . Then the rise in temperature d theta is.