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The straight lines 2x+3y-1-0, 3x+4y-6 = ...

The straight lines `2x+3y-1-0, 3x+4y-6 = 0` and `ax + by + 1=0` are concurrent if the straight line `14x + 9y + 1 = 0` passes through the point

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`2x+ 3y=1 & 3x+4y=6` On solving these equations we get,
`x=14, y=-9` The line ax+by+1=0 must passes through the point(14,-9).
Therefore, `14a-9b+1=0`.
Hence, the straight line ` 14x+9y+1=0 ` passes through `(a,-b)`.
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