`1(10)/(11)xx17 2/7xx36 1/6=?` (a) `397 5/6` (b) `397 1/2` (c) `1193 5/6` (d) `1193 1/2` (e) None of these

1(10)/(11)xx17(2)/(7)xx36(1)/(6)=?( a) 397(5)/(6) (b) 397(1)/(2) (c) 1193(5)/(6) (d) 1193(1)/(2) (e) None of these

(3.5xx1.4)/(0.7)=?( a) 0.7(b)2.4(c)3.5(d)7.1 (e) None of these

1(1)/(4)+1(5)/(9)xx1(5)/(8)-:6(1)/(2)=?( a) 17(b)27 (c) 18(d)42 (e) None of these

6(5)/(6)xx5(1)/(3)+17(2)/(3)xx4(1)/(2)=?( a) 112(1)/(3) (b) 116(2)/(3)(c)240(d)663(e) None of these

What is (7/8xx7/8+5/6xx5/6+2xx7/8xx5/3)/(7/8xx7/8-5/6xx5/6) equal to? (41)/(24) (b) 1/(24) (c) 41 (d) None of these

(3)/(4)(1+(1)/(3))(1+(2)/(3))(1-(2)/(5))(1+(6)/(7))(1-(12)/(13))=?(1)/(5)( b )(1)/(6)(c)(1)/(7) (d) None of these

2(1.5)/(5)+2(1)/(6)-1(3.5)/(15)=(((?)^(1/3))/(4))+1(7)/(30) (a) 2(b)8(c)512(d)324(e) None of these

6(6)/(6)xx5(1)/(3)+17(2)/(3)xx4(1)/(4)=?

The sum of the first 20 terms of the series (1)/(5xx6)+(1)/(6xx7)+(1)/(7xx8)+backslash is (a) 0.16(b)1.6c(c)16(d) None of these

Using appropriate properties find : (2)/(5) xx ((-3)/(7)) - (1)/(6) xx (3)/(2) + (1)/(14) xx (2)/(5) = (2)/(5) xx ((-3)/(7)) + (1)/(14) xx (2)/(5) - (1)/(cancel6) xx (cancel 3)/(2) = (2)/(5) xx ((-3)/(7) + (1)/(14) ) - (1)/(4) = (2)/(5) xx ((-6+1)/(14))- (1)/(4) = (cancel 2)/(cancel 5) xx (-cancel 5)/(cancel14) - (1)/(4) = (-1)/(7) - (1)/(4) (- 4 - 7)/(28) = (-11)/(28)