cos x cos2x cos3x=(1)/(4)

If cos x cos 2x cos 3x=1//4 , then x=

cos(x)cos(2x)cos(3x)=(1)/(4). Find the general solution.

1+ cos 2x+ cos4x + cos 6x= ............. A) 2 cos x cos 2x cos 3x B) 4 sin x cos 2x cos 3x C) 4 cos x cos 2x cos 3x D) 2 sin x cos 2x cos 3x

cos3x+cos2x+cos x=0

cos(x)cos(2x)cos(3x)=1/4 . Find the general solution.

cos(x)cos(2x)cos(3x)=1/4 . Find the general solution.

1+ cos 2x + cos 4 x+ cos 6x- 4 cos x cos 2x cos 3x =

Lim_(x->0)(1-cos x-cos2x+cos x cos2x)/(x^(4))

Prove : int cos x cos 2 x cos 3 x dx = 1/4 ( x+ (sin 2x)/2 + (sin 4x)/4 + (sin6x)/6 ) + c

Prove that: 1+cos2x+cos4x+cos6x=4cos x cos2x cos3x