`(a+b)tan(theta-phi)=(a-b)tan(theta+phi)` then `(sin 2theta)/(sin 2phi)=`

If (a+b)tan(theta-phi)=(a-b)tan(theta+phi) and a cos2 phi+b cos2 theta=c then prove that a^(2)-b^(2)+c^(2)=2ac cos2 phi

If (a+b)tan(theta-phi)=(a-b)tan(theta+phi) and a cos2 phi+b cos2 theta=c, then prove that a^(2)-b^(2)+c^(2)=2ac cos2 phi

If (a + b) tan (theta - phi) = (a-b) tan (theta + phi) " and " a cos 2 phi + b cos 2 theta = c, "show that" a^(2) -b^(2) + c^(2) = 2a cos 2 phi

If (a+b)tan(theta-phi)=(a-b)tan(theta-phi) and acos2phi+bcos2theta=c show that a^2-b^2+c^2=2a cos2phi

If (a-b)sin (theta+phi)=(a+b)sin(theta-phi) and a tan. (theta)/(2)-b tan.(phi)/(2)=c , then

If sin(theta+phi)=n sin(theta-phi), then the value of (tan theta)/(tan phi) is equal to

If (a-b) sin(theta + phi)=(a+b) sin(theta- phi) and atan(theta/2)-btan(phi/2)=c, then find the value of sinphi.

If sintheta=5sin(theta+phi) then tan(theta+phi)=

If sin theta=5sin(theta+phi) then tan(theta+phi)=