[2" In fig."/_DFE=90^(@)FG perp" ED,"1fGD=8],[FG=12" find "1" ) "EG" ,"2" FD "3" EF "],[qquad 8" ? "]

In the adjoining figure, angle DFE = 90^(@), FG bot ED if GD = 8, FG = 12 then find (i) EG (ii) FD (iii) EF.

In the adjoining figure, angleDFE=90^(@),FGbotED.IfGD=8,FG=12, find (i) EG (ii) FD, and (iii) EF

In the adjoining figure, angleDFE=90^(@),FGbotED.IfGD=8,FG=12, find (i) EG (ii) FD, and (iii) EF

In triangle DEF, /_DFE=90^@, FG_|_ED and D-G-E. If GD=8, FG=12, then find FD.

In triangle DEF, /_DFE=90^@, FG_|_ED and D-G-E. If GD=8, FG=12, then find EF.

In triangle DEF, /_DFE=90^@, FG_|_ED and D-G-E. If GD=8, FG=12, then find EG.

In Fig.4.139,/_ABC=90o and BD perp AC If BD=8cm,AD=4cm, find CD( FIGURE )

In the figure, /_DFE=90^(@) , seg FG bot side DE , DG=8 , FG=12 then complete the following activity to find the length of seg DE . In DeltaDFE , /_DFE=90^(@) , seg FG bot hypotenuse DE :. by theorem of geometric mean, FG^(2)=squarexxEG :.12^(2)=squarexxEG EG=(12xx12)/(square) :.EG=square DE=DG+GE=8+square=square

In DeltaDEF,"line " PQ||"side" EF.DQ=1.8, QF=5.4,PE=7.2."find" DE.