A particle starts from rest and moves under constant acceleration in a straight line. Find the ratio of displacement (a) in successive second and (b) in successive time interval `t_(0)`.

A particle starts from rest and moves under constant acceleration in a straight line. Find the ratio of time in successive displacement d .

A particle starts from rest and moves with constant acceleration. Then velocity displacement curve is:

A particle starts from rest and moves with constant acceleration. Then velocity displacement curve is:

A partical is moving in a straight line under constant acceletation. If the motion starts from rest, Find the ratio of displacement in n second to that in the n^(th) second.

A particle starting from rest moves along a straight line with constant acceleration for this velocity displacement graph will have the form-

A particle starting from rest moves along a straight line with constant acceleration for this velocity displacement graph will have the form-

A particle starts moving from position of rest under a constant acceleration if it travels a distance x in t second, what distance will it travel in next t second?

A particle starts from rest at t=0 and moves in a straight line with an acceleration as shown below. The velocity of the particle at t=3 s is

A particle starts from rest at t=0 and moves in a straight line with an acceleration as shown below. The velocity of the particle at t=3 s is

A particle, starting from rest, moves in a straight line with constant acceleration a_0 for a time interval t_0 .Then is accelerates at a constant rate 2a_0 for time interval 2t_0 .The distance travelled by the particle in time 3t_0 from the starts is S . Then (S)/(a_0t_0^(2) )=