Two cells of emf's `E_(1)` and `E_(2)` when placed in series produce null deflection at a distance of 204 cm in a potentio meter. When one cell is reversed they produce null deflection at 36 cm if `E_(1)` 1.4v then `E_(2)=`

Tow cells of e.m.f E_(1) and E_(2) are joined in series and the balancing length of the potentiometer wire is 625 cm. If the terminals of E_(1) are reversed , the balancing length obtained is 125 cm. Given E_(2) gt E_(1) ,the ratio E_(1) : E_(2) willbe

Tow cells of e.m.f E_(1) and E_(2) are joined in series and the balancing length of the potentiometer wire is 625 cm. If the terminals of E_(1) are reversed , the balancing length obtained is 125 cm. Given E_(2) gt E_(1) ,the ratio E_(1) : E_(2) willbe

The cells of emf's E_(1) and E_(2) be connector in parallel in a circuit. Let r_(1) and r_(2) be the internal resistance of the cells. Then the current through the circuit is

Two cells of emf E_(1) and E_(2) ( E_(1) gt E_(2)) are connected in series to potentiometer for balancing length 625 cm . When polarity of E_(2) is reversed then balancing length becomes 125 cm. Then the ratio (E_(1))/(E_(2)) is

In a potentiometer experiment two cells of e.m.f. E1 and E2 are used in series and in conjunction and the balancing length is found to be 58 cm of the wire. If the polarity of E2 is reversed, then the balancing length becomes 29 cm . The ratio (E_(1))/(E_(2)) of the e.m.f. of the two cells is

In a potentiometer experiment two cells of e.m.f. E1 and E2 are used in series and in conjunction and the balancing length is found to be 58 cm of the wire. If the polarity of E2 is reversed, then the balancing length becomes 29 cm . The ratio (E_(1))/(E_(2)) of the e.m.f. of the two cells is

In a potentiometer experiment two cells of e.m.f. E and E are used in series and in conjunction and the balancing length is found to be 58 cm of the wire. If the olarity of E is reversed, then the balancing length becomes 29 cm . The ratio (E_(1))/(E_(2)) of the e.m.f. of the two cells is