यदि `1, omega, omega^(2)` इकाई के घनमूल हो, तो सिद्ध कीजिए:
`(1)/(1+2omega)+(1)/(2+omega)-(1)/(1+omega)=0`

(1)/(1+2 omega)+(1)/(2+omega)-(1)/(1+omega)=0

(1)/(2+omega)+(1)/(1+2 omega)=(1)/(1+omega)

(1)/(2+omega)+(1)/(1+2 omega)=(1)/(1+omega)

(1)/(1+2omega)-(1)/(1+omega)+(1)/(2+omega)

If omega is an imaginary cube root of unity, then the value of (1)/(1+2omega)+(1)/(2+omega)-(1)/(1+omega) is :

If 1, omega , omega^2 are cube roots of unity prove that (1 / (1 + 2omega)) - (1 / (1 + omega)) + (1 / (2 + omega)) = 0

If 1 , omega , omega^(2) are the cube roots of unity, then prove that 1/(2 + omega) + 1/(1+2 omega) = 1/(1 + omega) .