If `S_r` denotes the sum of the first r terms of an A.P., then show that `(S_(3r)-S_(r-1))/(S_(2r)-S_(2r-1))` is equals

S_(r) denotes the sum of the first r terms of an AP.Then S_(3d):(S_(2n)-S_(n)) is -

If S_r denotes the sum of the first r terms of an A.P. Then, S_(3n)\ :(S_(2n)-S_n) is n (b) 3n (c) 3 (d) none of these

If S_r denotes the sum of the first r terms of an A.P. Then, S_(3n)\ :(S_(2n)-S_n) is n (b) 3n (c) 3 (d) none of these

Let S_(n) denote the sum of the cubes of the first n natural numbers and S'_(n) denote the sum of the first n natural numbers, then underset(r=1)overset(n)Sigma ((S_(r))/(S'_(r))) equals to

in an AP , S_p=q , S_q=p and S_r denotes the sum of the first r terms. Then S_(p+q)=

If S _(r) denote the sum of first 'r' terms of a non constaint A.P. and (S_(a ))/(a ^(2)) =(S_(b))/(b ^(2))=c, where a,b,c are distinct then S_(c) =

If S _(r) denote the sum of first 'r' terms of a non constaint A.P. and (S_(a ))/(a ^(2)) =(S_(b))/(b ^(2))=c, where a,b,c are distinct then S_(c) =

in an AP,S_(p)=q,S_(q)=p and S_(r) denotes the sum of the first r terms.Then S_(p+q)=

let S_(n) denote the sum of the cubes of the first n natural numbers and s_(n) denote the sum of the first n natural numbers , then sum_(r=1)^(n)(S_(r))/(s_(r)) equals to

let S_(n) denote the sum of the cubes of the first n natural numbers and s_(n) denote the sum of the first n natural numbers , then sum_(r=1)^(n)(S_(r))/(s_(r)) equals to