26xy(x+5)(y-4)-:13x(y-4)

Divide as directed. 26xy(x+5) (y - 4) div 13x(y -4)

x^(4)y-xy^(4)

y=x^(4)-6x^(3)+13x^(2)-10x +5 at (0,5).

Find the equations of the tangent and normal to the given curves at the indicated points : (i) y=x^(4)-6x+13x^(2)-10x+5" at "(0, 5) (ii) y=x^(4)-6x^(3)+13x^(2)-10x+5" at "(1, 3) . (iii) y= x^(3)" at " (1, 1) (iv) y=x^(2)" at " (1, 1) (v) x =cost, y = sin t" at "y=(pi)/(4) .

Add the algebraic expressions: (11)/(2)xy+(12)/(5)y+(13)/(7)x,-(11)/(2)y-(12)/(5)x-13xy

(a) If x : y = 3 : 4 , then find the value of the ratio (2x + y) : ( 9x - 2y) . (b) If x : y = 5 : 4 , then find the value of the ratio (x^(2) + xy) : (x^(2) - xy) .

Show that: (x^(2)+y^(2))^(5)=(x^(5)-10x^(3)y^(2)+5xy^(4))^(2)+(5x^(4)-10x^(2)y^(3)+y^(5))^(2)

If y=x^(4)-6x^(3)+13x^(2)-11x+4 , then approximate valueof y when x=2.01 is