A foce acts on a 30.g particle in such a way that the position of the particle as a function of time is given by
`x=3t-4t^(2)+t^(3)`, where x is in metre and t in second. The work done during the first 4s is

A foce acts on a 30g particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where x is in metre and t in second. The work done during the first 4s is

A force acts on a 3.0 gm particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where xx is in metres and t is in seconds. The work done during the first 4 seconds is

A force acts on a 3.0 gm particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where xx is in metres and t is in seconds. The work done during the first 4 seconds is

A force act on a 30 gm particle in such a way that the position of the particle as a function of time is given by x = 3 t - 4 t^(2) + t^(3) , where x is in metros and t is in seconds. The work done during the first 4 second is

The position of a Particle of Mass 4 g,acted upon by a constant force is given by x= 4t^(2) +t,where x is in metre and t in second .The work done during the first 2 seconds is

Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in metre and t in second. The work done by the force in the first two seconds is .

The position of the particle moving along x-axis is given by x=2t-3t^(2)+t^(3) where x is in mt and t is in second.The velocity of the particle at t=2sec is