A body is dropped from a height of `40 m`. After it crosses half distance, the acceleration due to gravity ceases to act. The body will hit ground with velocity `("Take" g = 10 m//s^2)` :

A body is dropped from a height of 39.2 m. After it crosses half distance, the acceleration due to gravity ceases to act. The body will hit the ground with velocity ( Take g=10 m//s^(2) )

A body is dropped from a height 39.2m. After it crosses half distance , the acceleration due to gravity ceases to act. The body will hit the ground with velocity.

A melon is dropped from a height of 39.2 m. After it crosses through half that distance , the acceleration due to gravity is reduced to zero by air drag. With what velocity does the melon hit the ground ?

A body is dropped from a height 135 m. If after 3 sec acceleration due to gravity of earth cases to act then the further time of descent is (g=10 "m/s"^2)

A body is dropped from a height 135 m. If after 3 sec acceleration due to gravity of earth cases to act then the further time of descent is (g=10 "m/s"^2)

A body is dropped from a height of 100m. At what height the velocity of the body will be equal to one half of the velocity when it hits the ground ?