" 18.(i) "5^(x)

Solve each of the following equations by using the formula : (i) 5x^(2)-2x-3=0 (ii) x^(2)=18x-77

The 13 th term in the expansion of (9x-1/(3sqrt(x)))^(18),x gt0 is (i) ""^(18)C_(12)x^(3) (ii) ""^(18)C_(12)x^(6) (iii) ""^(18)C_(12)1/(x^(6)) (iv) ""^(18)C_(12)

Find the value of: (i) (987)^(2)-(13)^(2) (ii) ((18.5)^(2)-(6.5)^(2))/(18.5 + 6.5)

The displacement (in metre) of a particle moving along x-axis is given by x=18t +5t^(2) Calculate (i) instantaneous acceleration.

I. (17)^(2) + 144 div 18 = x" " II. (26)^(2) - 18 xx 21 = y

Simplify : (i) (-2)/3+5/9-(-7)/6 (ii) 5/(12)+(-5)/(18)-7/(24)

Simplify : (i) (-2)/3+5/9-(-7)/6 (ii) 5/(12)+(-5)/(18)-7/(24)