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" 10."quad (1)(1+x)(1+y^(2))dx+(1+y)(1+x...

" 10."quad (1)(1+x)(1+y^(2))dx+(1+y)(1+x^(2))dy=0

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(1+x^(2))dx+(1+y^(2))dy=0

Solve the differential equation (1+x)(1+y^(2))dx+(1+y)(1+x^(2))dy =0.

x(2y-1)dx+(x^(2)+1)dy=0

y(1+x^(2))dy=x(1+y^(2))dx

y(1-x^(2))dy=x(1+y^(2))dx

x(1+y^(2))dx+y(1+x^(2))dy=0 at (0, 0)

Solve the differential equation : x (1 + y^2) dx - y (1 + x^2) dy = 0 given that y = 0 when x = 1

(dy)/(dx)=(y^(2)+y+1)/(x^(2)+x+1)

(dy)/(dx)=(y^(2)-y+1)/(x^(2)-x+1)