Home
Class 6
MATHS
Find the smallest number greater than 2 ...

Find the smallest number greater than 2 which gives a remainder 2 when divided by 16,18 and 24.

Text Solution

Verified by Experts

The correct Answer is:
146
The requird number is the least common multiples of (16,18,24)+2.

`LCM=2xx2xx2xx3xx2xx3=144`
`:.` The required number is 144+2=146
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • FACTORS AND MULTIPLES

    PEARSON IIT JEE FOUNDATION|Exercise Concept Application|5 Videos

  • FACTORS AND MULTIPLES

    PEARSON IIT JEE FOUNDATION|Exercise Assessment Test|15 Videos

  • FACTORS AND MULTIPLES

    PEARSON IIT JEE FOUNDATION|Exercise Test Your Concepts ( Match the Column ) :|1 Videos

  • ALGEBRA

    PEARSON IIT JEE FOUNDATION|Exercise CROSSWORD|1 Videos

  • FRACTIONS AND DECIMALS

    PEARSON IIT JEE FOUNDATION|Exercise Crossword|1 Videos

Similar Questions

Explore conceptually related problems

Find the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively.

Find the lowest number which gives a remainder 3 when divided by any of the numbers 6, 7 and 8.

Knowledge Check

  • Find the smallest number which leave remainder 2, when divided by 6, 9,12, 15 and 18?

    A
    180
    B
    182
    C
    178
    D
    176

  • Find the least number which when divided by 12, leaves a remainder 7, when divided by 15, leaves a remainder 10 and when divided by 16, leaves a remainder 11

    A
    115
    B
    235
    C
    247
    D
    475

  • Find the least number greater than 10 which when divided by 15,20 and25 leaves remainder 10 in each case.

    A
    290
    B
    300
    C
    310
    D
    320

    • Similar Questions

    Explore conceptually related problems

    Which of the following is the smallest positive integer which gives the remainder 3when divided with 4,6,8, and 10?

    What is the smallest number which leaves remainder 3 when divided by any of the numbers 5, 6 or 8 but leaves no remainder when it is divided by 9

    What is the smallest number which leaves remainder 3 when divided by any of the numbers 5, 6 or 8 but leaves no remainder when it is divide by 9 ?

    Find the remainder when 5^(18) is divided by 19.

    a and b are any numbers and x and y are any non negative integers. l(a) = the greatest integer less than or equal to a g(a) = the smallest integer greater than or equal to a r(x,y) = the remainder when x is divided by y. r(16, 7)-2 is equal to :

    Home
    Profile