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In how many years, a certain sum becomes...

In how many years, a certain sum becomes tripe itself at `12%` p.a.?

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The correct Answer is:
`16(2)/(3)`years
Rare`=12%`pa
T=?
`A=3P
I=A-P=3P-P=2P`
`T=(100I)/(PR)`
`T=(100xx2P)/(Pxx12)=(100)/(6)=(50)/(3)=16(2)/(3)` years
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