AC voltage source `(V, omega)` is applied across a parallel LC circuit as shown in figure. Find the impedance of the circuit and phase of current.

An AC voltage source V=V_0sinomegat is connected across resistance R and capacitance C as shown in figure. It is given that omegaC=1/R . The peak current is I_0 . If the angular frequency of the voltage source is changed to omega/sqrt3, then the new peak current in the circuit is .

An AC voltage source is applied across an R-C circuit. Angular frequency of the source is omega , resistance is R and capacitance is C. The current registered is I. If now the frequency of source is changed to omega/2 (but maintaining the same voltage), the current in the circuit is found to be two third. calculate the ratio of reactance to resistance at the original frequency omega .

An alternative voltage V = 10 sin omega t (in volts) is applied across a parallel arrangement as shown current (in A ) through the source is best described by

An ac voltage of 100V,50Hz is connected across a 20Omega resistor and 2mH inductor in series. Calculate (i) impedance of the circuit (ii) rms current in the circuit.

An rms voltage of 110 V is applied across a series circuit having a resistnce 11 Omega and an impedance 22 Omega . The power consumed is

An ac source of voltage V=V_(m)sin omega t is connected across the resistance R as shown in figure. The phase relation between current and voltage for this circuit is