" Solve: "cos(60^(@)+theta)-sin(30^(@)-theta)

Solve cos(50^(@)+ theta) = sin (30^(@)+theta) .

If 4 sin(60^(@) + theta ) sin (60^(@) - theta )-1=k cos 2 theta , the value of k is

cos theta - cos (60^(@) + theta ) - cos(60^(@) - theta )=

Prove that: sin(60^(@)-theta)cos(30^(@)+theta)+cos(60^(0)-theta)sin(30^(@)+theta)=1

sin (60^(@) + theta) - sin ( 60^(@) - theta ) = sin theta.

Evaluate sin(30^(@)+theta)-cos(60^(@)-theta) .

Evaluate sin(30^(@)+theta)-cos(60^(@)-theta) .

Solve cos^(4)theta-sin^(4)theta=cos^2theta

cos theta cos (60^(@) + theta ) * cos (60^(@) - theta ) =

I : cos^2 theta + cos^(2) (60^@ + theta ) + cos^(2) (60^@ - theta ) = 3//2 II : sin^(2) theta + sin^(2)(60^(@) + theta ) + sin^(2)(60^(@) - theta ) =3//2