(2x+3)^(2)=25

Solve the quadratic equation for x: ( 2 x + 3)^(2) = 25

x^(2)+y^(2)-4x-6y+9=0 and (x+3)^(2)+(y+2)^(2)=25 are two circles. The lines x=2 is a

The equation of the ellipse whose vertices are (9,2),(-1,2) and the distance between the foci is 8 unit is (A)9(x-3)^(2)+25(y-4)^(2)=225(B)9(x+3)^(2)+25(y+4)^(2)=225(C)9(x-4)^(2)+25(y-3)^(2)=225(D)9(x+4)^(2)+25(y+3)^(2)=225

A line y=mx+1 meets the circle (x-3)^(2)+(y+2)^(2)=25 at point P and Q. if mid point of PQ has abscissa of -(3)/(5) then value of m satisfies

A line y=mx+1 meets the circle (x-3)^(2)+(y+2)^(2)=25 at point P and Q. if mid point of PQ has abscissa of -(3)/(5) then value of m satisfies

The radius of the circle which touches circle (x+2)^(2)+(y-3)^(2)=25 at point (1,-1) and passes through (4,0) is (a) 4 (b) 5 (c) 3 (d) 8

The parametric representation of the circel (x-3) ^(2 ) + (y+4)^(2) =25 is

The parametric representation of the circel (x-3) ^(2 ) + (y+4)^(2) =25 is

Which of the following points lies on the circumference of the circle (x-2)^(2) + (y+3)^(2) = 25 ?