In a hydraulic jack as shown, mass of the car `=W=800kg, A_(1)=10cm6(2), A_(2)=10m^(2)`. What is the the minimum force F required to lift the car ? Take `g=10m//s^(2)`

Explanation

To solve the problem of finding the minimum force \( F \) required to lift the car using a hydraulic jack, we can use the principle of hydraulic systems, which states that the pressure applied to a confined fluid is transmitted undiminished throughout the fluid.

### Step-by-Step Solution:

1. **Identify the Given Values**:
- Mass of the car, \( W = 800 \, \text{kg} \)
- Area of piston 1, \( A_1 = 10 \, \text{cm}^2 = 10 \times 10^{-4} \, \text{m}^2 = 10^{-3} \, \text{m}^2 \)
- Area of piston 2, \( A_2 = 10 \, \text{m}^2 \)
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