Two bodies are in equilibrium when suspended in water from the arms of a balance.The mass of one body is `28 g` and its density is `5.66 g//cm^3`. If the mass of the other body is `36 g`, what is its density ?

Explanation

`"Apt. wt. of 1st body"=m_(1)g-F_(b)=(28-(28)/(5.6))g.`
`"Apt wt. of 2nd body"=m_(2)g-F_(b)=(36-(36)/(d)xx1)g`
`because" bodies are in equilibrium apt wts.are equal"`
`(28-(28)/(5.6))g=(36-(36)/(d))g,(28-(2.8)/(5.6))=36-(36)/(d)`
`rArr (36)/(d)=36-23=13, d=(36)/(13)~~2.8g//c c`.