A hose shoots water straight up to a height of 2.5 m. The opening end of the hose has an area of `0.75cm^(2)`. What is the speed of the water as it leaves the hose? How much water will come out in one minute?

Explanation

Kinetic energy at bottom = Potential energy at the top
`(1)/(2)v^(2)=gh rArr v=sqrt(2gh)rArr v=sqrt(2xx9.8xx2.5)`
`=sqrt(5x9.8)=sqrt(49)=7m//s, v=7m//s or 700cm//s`.
The rate of flow of water = Av. So in one minute the volume of water heat that flows out
`=Avxx60=(0.75)xx700xx60=0.75xx42xx10^(3)`
`=3.15xx10^(4)cm^(3)="31.5 litre."`