A water drop of diameter 2 mm is split up into `10^(9)` identical water drops. Calculate the work done in this process. (the surface tension of water is `7.3xx10^(-2)Nm^(-1))`

Explanation

Let a water drop of radius R be split up into `10^(9)` identical water drops each of radius r.
`R=(D)/(2)=(2)/(2)=1mm=1xx10^(-3)m`
`"No. droplets n "=10^(9)," "T=7.3xx10^(-2)Nm^(-1)`
`W=4piR^(2)T[n^(1//3)-1]`
`=4pi(10^(-3))^(2)xx7.3xx10^(-2)[(10^(9))^(1//3)-1]=9.17xx10^(-4)J`