A drop of radius R is split under isothermal condition into into `n` droplets each of radius `r` the ratio of surface energies of big and each small drop is

Explanation

`(U_("big"))/(U_("small"))=((4piR^(2))T)/((4pir^(2))T)=(R^(2))/(r^(2))=((n^(1//3)r)^(2))/(r^(2))=n^(2//3):1`