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Two soap bubble of radii R(1) and R(2) a...

Two soap bubble of radii `R_(1)` and `R_(2)` are kept in vacuum at constant temperature, the ratio of masses of air inside them, is

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`"From, PV"=(m)/(M)RT" i.e., "m prop PV`
`P_(1)=P_(0)+(4T)/(R_(1))=0 +(4T)/(R_(1)), P_(2)=P_(0)+(4T)/(R_(2))=0+(4T)/(R_(2))`
`(m_(1))/(m_(2))=(P_(1)V_(1))/(P_(2)V_(2))=(((4T)/(R_(1)))(4)/(3)piR_(1)^(3))/(((4T)/(R_(2)))(4)/(3)piR_(2)^(3))therefore (m_(1))/(m_(2))=(R_(1)^(2))/(R_(2)^(3))`
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NARAYNA-MECHANICAL PROPERTIES OF FLUIDS-Illustration
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