Home
Class 11
PHYSICS
If W is amount of work done in forming a...

If W is amount of work done in forming a soap bubble of volume V , then the amount of work done In forming a bubble of volume 2V from the same solution will be

A

`2^(1//2)W`

B

`3^(1//3)W`

C

`4^(1//2)W`

D

`4^(1//3)W`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • MECHANICAL PROPERTIES OF FLUIDS

    NARAYNA|Exercise EVALUATE YOURSELF - 11|4 Videos
  • MECHANICAL PROPERTIES OF FLUIDS

    NARAYNA|Exercise EVALUATE YOURSELF - 12|3 Videos
  • MECHANICAL PROPERTIES OF FLUIDS

    NARAYNA|Exercise EVALUATE YOURSELF - 9|3 Videos
  • MATHEMATICAL REVIEW & PHYSICAL WORLD

    NARAYNA|Exercise C.U.Q|13 Videos
  • MECHANICAL PROPERTIES OF SOLIDS

    NARAYNA|Exercise LEVEL-II (H.W)|24 Videos

Similar Questions

Explore conceptually related problems

The work done is blowing a soap bubble of volume V is W the work done in blowing a soap bubble of volume of 2V is

The work done is blowing a soap bubble of volume V is W . The work done in blowing a soap bubble of volume 2V is

The work done in blowing a bubble of volume V is W , then what is the work done in blowing a soap bubble of volume 2V ?

The work done in blowing a soap bubble of radius 5 cm is

Work done in forming a soap bubble of radius R is W. Then workdone is forming a soap bubble of radius '2R' will be :

Work done is blowing a soap bubble of diameter 2 cm , is

If work W is done in blowing a bubble of radius R from a soap solution. Then the work done is blowing a bubble of radius 2R from the same solution is

If work done in blowing a bubble of radius R is in a soap solution , then the work done in blowing a bubble of radius halved in same solution would be ,

The work done in blowing a soap bubble of radius 0.02 cm is ,