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Two liquids are allowed to flow through two capillary tubes of length in the ratio `1:2` and radii in the ratio `2:3` under the same pressure difference. If the volume rates of flow of the liquids are in the ratio `8:9` the ratio of their coefficients of viscosity is

A

`1:3`

B

`3:1`

C

`4:9`

D

`9:4`

Text Solution

Verified by Experts

The correct Answer is:
C
`Q=(piPr^(4))/(8etal), eta alpha(r^(4))/(Ql)`
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